Q12 pls

Q12 pls and Ies . If tan A + cot A = 5; find the value of tan2 A + cot2 A.Qz 12. Given : 4 sin 0 = 3 cos 0; find the valueof.. (i) sin 0 (ii) cos 0 (iii) cot2 0 — cosec2 0. (iv) 4 cos2 0 — 3 sin2 0 + 2 13. Given : 17 cos e = 15; find the value of tan 0 + 2 sec 0. 14. Given: 5 cos A — 12 sin A = 0; evaluate sin A + cos A

the answer will be 3
 
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MAY BE 3
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tanA +cotA=5 Squaring both sides we get tan2A +cot2A+2tanAcotA =25 tan2A +cot2A =25-2×tanA×1/tanA tan2A + cot2A=23
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