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Q14.

Ans given as : option b.

Q.14. 1 mole of a diatomic element ${X}_{2}$ contains 34 and 40 moles of electrons and neutrons respectively. The isotopic formula of the element is

(a) ${}_{34}{}^{74}X$

(b) ${}_{17}{}^{37}X$

(c) ${}_{34}{}^{40}X$

(d) ${}_{20}{}^{40}X$

Please find below the solution of your asked query:

If one X

_{2}molecule contains

**34 electrons**and

**40 neutrons**, then one atom of X has

**17 electrons**and 20 neutrons. Assuming that it is electrically neutral, it will also have 17 protons. The isotope has an

**atomic number of 17**(number of protons), and a

**mass number of 37**(number of protons + number of neutrons).

So, the isotopic formula of the element will be ${}_{\mathbf{17}}{}^{\mathbf{37}}\mathbf{X}$.

Therefore, option (b) is correct.

Hope this information clears your doubts about the topic.

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