# Q14.... Plss Urgent

${F}_{electrostatic}=mg\phantom{\rule{0ex}{0ex}}\frac{kqq}{{r}^{2}}=mg\phantom{\rule{0ex}{0ex}}{r}^{2}=\frac{k{q}^{2}}{mg}\phantom{\rule{0ex}{0ex}}r=\sqrt{\frac{k{q}^{2}}{mg}}=q\sqrt{\frac{k}{mg}}=1.6\times {10}^{-19}\sqrt{\frac{9\times {10}^{9}}{1.7\times {10}^{-27}\times 9.8}}=0.117m\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Regards$

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