Q   15 .   I n   t h e   g i v e n   f i g u r e ,   D E B C .   F i n d   t h e   m e a s u r e   o f   x   a n d   y









Q   16 .   I n   t h e   f i g u r e   g i v e n   b e l o w ,   p q   a n d   r s .   F i n d   t h e   v a l u e   o f   x , y , z .












Q   17 .   I n   t h e   g i v e n   f i g u r e   p q .   F i n d   t h e   v a l u e s   o f   x , y , z .

15.


Since, DEBC and AB is a transversal, thenDAB = ABC    Alternate interior angles3x + 40 = x - 603x - x = -60 - 402x = -100x = -50;  not possibleSince, DEBC and ACis a transversal, thenEAC= ACM   Alternate interior angles2y+25 = y+202y-y = 20-25y = -5; not possibleKindly recheck your question.

Kindly ask the remaining queries in different threads.

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try by your own
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Hi Punyak,
I tried it was not able to solve these questipns pf my book. Also, if i would have known the answers, why would I post on meritnation. If you know the answer send it please with the steps.
Thank you
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