Q16 Option(2) How â ‹Q16 Given - Chemistry -

Question

Q16
Option(2) How?

â€‹Q16 Given

Reaction
Energy Change (in kJ)

Li(s) → Li(g)
Li(g) → Li+(g)

1 2 F 2 g → F g
F(g) + e¯ → F¯(g)
Li+(g) → F¯(g) → LiF(s)
Li (s) + 1 2 F2(g) → Li F(s)
161
520

77

(Electron gain enthalpy)

–1047

–617

Based on data provided, the value of electron gain enthalpy of
fluorine would be :

(1) – 300 kJ mol–1 (2) – 328 kJ
mol–1 (3) – 350 kJ mol–1
(4) – 228 kJ mol–1

Shireen Aaisha · Accepted Answer

Reaction	Energy Change (in kJ)
Li(s) $\to$ Li(g) Li(g) $\to$ Li⁺(g) $\frac{1}{2} F_{2} (g) \to F (g)$ F(g) + e¯ $\to$ F¯(g) Li+(g) $\to$ F¯(g) $\to$ LiF(s) Li (s) + $\frac{1}{2}$ F2(g) $\to$ Li F(s)	161 520 77 (Electron gain enthalpy) –1047 –617