Q16

Dear student

Let A and B are two vectors which makes an angle θ with each other. Then
    A+2B·2A-3B=2A·A-3A·B+4B·A-6B·Bbut A·A=A2, B·B=B2 and A·B=B·A=ABcosθ hence=2A2+ABcosθ-6B2 

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