Q2 A denser medium of refractive index 1 5 has a concave surface of radius of curvature 12 cm - Science - Work and Energy

Question

Q2 A denser medium of refractive index 1 5 has a concave surface of
radius of curvature 12 cm An object is situated in the denser
medium at a distance of 9 cm from the pole Locate the image due to
refraction in air
(1) A real image at 8 cm (2) A virtual image at 8 cm
(3) A real image at 4 8 cm (4) A virtual image at 4 8 cm

Q3 In a medium of refractive index 1 6 and having a convex surface
has a point object in it at a distance of 12 cm from the pole The
radius of curvature is 6 cm Locate the image as seen from air
(1) A real image at 30 cm (2) A virtual image at 30 cm
(3) A real image at 4 28 cm (4) A virtual image at 4 28 cm

Pintu Biswas · Accepted Answer

Dear Student ,
Here in this case the refraction at a concave surface is given by
,
n2v-n1u=n2-n1RWhere n1=refracting index of the refracting medium=1·5 ,n2=refracting index of the medium in which the light was travelling initiallyusually air=1,v=image distance ,u=object distance=9 cm ,R=radius of curvature of the refracting surface=12 cm 
Now substituting this values in the above equation we get ,1v-1·59=1-1·512⇒1v=1·59-1-1·512⇒v=8 cmNow the image will be virtual image and the image distance will be 8 cm 
Hope this helps you
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