Ans: B.
Help asap.

Q2. Ans: B. Help asap. N p amss:an ul pur " S SUJOIE g JO •ou umununu - . V pur • Aa W 0 sati-xau• wutSuo JO D(.urg iO OJ

Dear student

the energies of the photons emitted can be expressed as13.6112-122eV =0.6613.6112-132eV =1.8913.6122-132eV =2.55
the transition can be shown as
energy of photon transition
1.89 n=3 to n=1
2.55 n=3 to n=2
0.66 n=2 to n=1

so option (D) is correct


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