Q21.
Ans:C how?

Dear Student,

Please find below the solution to the asked query:

Given  : The probability that horse 1 would win is $\frac{1}{6}$ , that horse 2 would win is $\frac{1}{10}$ and that horse 3 would win is $\frac{1}{8}$. Assuming that a tie is impossible, So

The chance that one of the three will win = $\frac{1}{6}$ + $\frac{1}{10}$ + $\frac{1}{8}$= $\frac{20 + 12 + 15}{120} = \frac{\mathbf{47}}{\mathbf{120}}$                       



Regards