Q24. Is k=12? In Meritnation answer key, it's given k=6! (Top 100 Que) Q.24. For what value of k will the consecutive terms 3k + 2, 4k + 5 and 6k - 4 form an AP? Share with your friends Share 2 Sanjari Kalantri answered this Dear Student, Given: 3k + 2, 4k + 5, 6k - 4 are consecutive terms of an AP⇒ 4k + 5 - 3k + 2 = 6k - 4 - 4k + 5⇒ 4k + 5 - 3k - 2 = 6k - 4 - 4k - 5⇒ k + 3 = 2k - 9⇒ k = 12 3 View Full Answer Dhyey Mistri answered this k=6 1
