Q4 4 . lim h → 0 tan a + 2 h - 2 tan a + h + tan a h 2 i s e q u a l t o A tan a B tan 2 a C s e c a D 2 s e c 2 a tan a Share with your friends Share 2 Aarushi Mishra answered this limh→0 tan a+2h-2 tan a+h+tan ah2=limh→0 tan a+2h-tan a+h+tan a-tan a+hh2=limh→0 tan a+2h-tan a+h+tan a-tan a+hh2=limh→0 sin a+2hcos a+2h-sin a+hcos a+h+sin acos a-sin a+hcos a+hh2=limh→0 sin a+2h cos a+h-sin a+h cos a+2hcos a+2h cos a+h+sin a cos a+h-sin a+h cos acos a cos a+hh2Use sin x cosy-cos x sin y=sinx-y=limh→0 sin hcos a+2h cos a+h+sin -hcos a cos a+hh2=limh→0 sin hcos a+2h cos a+h-sin hcos a cos a+hh2=limh→0 sin hh×1cos a+2h-1cos ah cos a+h=limh→0 sin hh×cos a-cos a+2hcos a+2h cos ah cos a+hUse cos x-cos y=2 sinx+y2 siny-x2=limh→0 sin hh×2 sin 2a+2h2 sin a+2h-a2cos a+2h cos ah cos a+h=limh→0 sin hh×2 sin a+h sin hcos a+2h cos ah cos a+h=limh→0 sin hh2×2 sin a+hcos a+2h cos acos a+h=limh→0sin hh2×limh→02 sin a+hcos a+2h cos alimh→0cos a+hUse limx→0sin xx=1=12×2 sin acos a cos acos a=2 tan acos2a=2 tan a sec2a 5 View Full Answer Light answered this Just differentiate it 4