Q5 pls solve fast

Q5 pls solve fast graph Of a cyclist. average in first S. displ.u-emenr from initial at end of 10 Ciii) the after which he reaches the starting Fig. 239 Ans. (i) 25m —10m, (iii)7sand 13 s. Fig 2.40 ahead represents the displacement—time displacement of body and 4 then draw the di for it on Fig. 2.41 TIME (S) Fig. 2.41 Fig. 2.42 given below shows a graph for a car starting from has three parts AB. BC and CD- c

Dear student,

1) Average velocity v_avg = total displacement / total time = 10/4 =2.5m/s

2) At the end of 10 seconds the body is at -10 m and initially it was at 0m. So the displacement is final position - initial position.
Displacement = -10 m

3) Since the starting point is 0 m and the displacement is 0 at 7 seconds and 13 seconds so 7 s and 13 s are the times when the particle again reaches the starting position.

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