Q68 If the minimum radius of the circle which contains the three circles x2 + y2 - 4y - - Maths -

Question

Q68 If the minimum radius of the circle which contains the three
circles x2 + y2 - 4y - 5 = 0 , x2
+ y2 + 12x + 4y + 31 = 0 & x2 +
y2 + 6x + 12y + 36 = 0 is 3 + 5 36 λ , then the
value of λ must be?

Lovina Kansal · Accepted Answer

Dear student

So,on comparing, we get λ=949 Regards

Q68. If the minimum radius of the circle which contains the three circles x2 + y2 - 4y - 5 = 0 , x2 + y2 + 12x + 4y + 31 = 0 & x2 + y2 + 6x + 12y + 36 = 0 is 3 + 5 36 λ , then the value of λ must be?

Q68. If the minimum radius of the circle which contains the three circles x² + y² - 4y - 5 = 0 , x² + y² + 12x + 4y + 31 = 0 & x² + y² + 6x + 12y + 36 = 0 is $(3 + \frac{5}{36} \sqrt{λ})$ , then the value of $λ$ must be?