Q7 ,9 ii ch triangle

Dear Student,

$$\begin{gathered} \mathrm{Difference} \mathrm{in} \mathrm{height} \mathrm{is} \left(18-13\right)\mathrm{m} = 5 \mathrm{m}, \mathrm{So} \mathrm{AE} = 5 \mathrm{m} \\ \mathrm{The} \mathrm{distance} \mathrm{between} \mathrm{the} \mathrm{feet} \mathrm{is} 12 \mathrm{m}, \mathrm{So} \mathrm{DE} = 12 \mathrm{m} \\ \mathrm{We} \mathrm{can} \mathrm{apply} \mathrm{pythagoras} \mathrm{theorem}, \\ \mathrm{Let} \mathrm{AD} =\mathrm{d} \\ \mathrm{d} = \sqrt{{\left(5\right)}^2+{\left(12\right)}^2} \\ \mathrm{d} = \sqrt{25+144} \\ \mathrm{d} =\sqrt{169} \\ \mathrm{d} = 13 \mathrm{m} \end{gathered}$$

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