Q8 plssss help Share with your friends Share 0 Atul Shaw answered this Dear student,Let, α=A; β=B; γ=C; δ=Dsin(B-C) cos(A-D)+sin(C-A) cos(B-D)+sin(A-B) cos(C-D)∘sin(B-C) cos(A-D)=(sin B cos C-cos B sin C)(cos A cos D+sin A sin D)=cos A sin B cos C cos D+sin A sin B cos C sin D- cos A cos B sin C cos D -sin A cos B sin C sin D∘sin(C-A) cos(B-D)=(sin C cos A-cos C sin A)(cos B cos D+sin B sin D)=cos A cos B sin C cos D+cos A sin B sin C sin D- sin A cos B cos C cos D - sin A sin B cos C sin D∘sin(A-B) cos(C-D)=(sin A cos B-cos A sin B)(cos C cos D+sin C sin D)=sin A cos B cos C cos D+sin A cos B sin C sin D-cos A sin B cos C cos D-cos A sin B sin C sin DTherefore:sin(B-C) cos(A-D)+sin(C-A) cos(B-D)+sin(A-B) cos(C-D)=cos A sin B cos C cos D+sin A sin B cos C sin D- cos A cos B sin C cos D -sin A cos B sin C sin D+ cos A cos B sin C cos D+cos A sin B sin C sin D- sin A cos B cos C cos D - sin A sin B cos C sin D+ sin A cos B cos C cos D+sin A cos B sin C sin D-cos A sin B cos C cos D-cos A sin B sin C sin D=0option B is correctRegards 1 View Full Answer
