Q84.
Ans: option d.
Why not option c or e?

Q84. Ans: option d. Why not option c or e? osZ14 (p) E I-Id (q) [Sooz OZH (D) E I-IN (e) Olfiue puoq »oueu_ls ouo solnootoul fiuourv

Dear Student,

Bond angles of following compounds are :


H 2 O   →   104 .
5 ° H 2 S   →     92 . 5 °
N H 3   →   106 . 5 ° 
PH3   →   93 . 5 ° ,
 H2Se → 91° 
  • Since,  in H2S the 'lone pair-lone pair' and 'lone pair-bond pair' repulsions are reduced due to the larger size of sulphur atom. Thus, it has the smallest bond angle.
  • While, in other cases like H2O and NH3 repulsions are greater due to smaller size. Thus, their bond angle is larger.
  • And in case of  H2Se  its bond angle is 91° , smallest
Therefore, option (d) is correct.

 
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The h2s is smallest
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because it has very less bonds between them as Sc valancy is 2 and 2 hydrogen is used
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