QP ll TS and angle QRS =36 0 ,Calculate angle PQR
Dear Student,
Please find below the solution to the asked query:
We have our diagram , As :
Here we extend line TS that intersect line QR at " U " , So TU | | QP ( As given QP | |TS and TU is part of TS )
So we take QR as transversal line , So
PQR = QUS = x ( Alternate interior angles )
And
QUS + SUR = 180 ( Linear pair angles )
x + SUR = 180
SUR = 180 - x ---- ( 1 )
And
TSR + USR = 180 ( Linear pair angles )
2 x + USR = 180
USR = 180 - 2 x ---- ( 2 )
And from angle sum property of triangle we get in triangle SRU :
SRU + USR + SUR = 180 , Substitute values from equation 1 and 2 and SRU = 36 ( Given ) and get
36 + 180 - 2 x + 180 - x = 180
36 + 180 - 3 x = 0
3 x = 216
x = 72
Therefore,
PQR = 72 ( Ans )
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