QS and RT are the altitudes at triangle PQR .qs is equal to rt .
Is triangle PQS congruent to triangle SQR.by which congruence condition.<<<<<<????
Hi!
∆PQS and ∆SQR can not be proved as congruent.
But, we can prove that ∆QRS ≅ ∆RQT.
In ∆QRS and ∆RQT,
QS = RT (given)
QR = RQ (common side)
∠QSR = ∠QTR (90°)
Hence, ∆QRS ≅ ∆RQT (RHS congruence criterion)
Cheers!