Dear Student, cotB2cotC2= ss-bs-as-c×ss-cs-as-b= ss-aNow from the given b+c=3a a+b+c = 3a+a2s = 4a s = 2a Putting this we get =2a2a-a= 2 Regards

ques. 8

Dear Student, \cot \frac{B}{2} \cot \frac{C}{2} = \sqrt{\frac{s (s - b)}{(s - a) (s - c)} \times \frac{s (s - c)}{(s - a) (s - b)}} = \frac{s}{s - a} Now from the given b + c = 3 a a + b + c = 3 a + a 2 s = 4 a s = 2 a Putting this we get = \frac{2 a}{2 a - a} = 2 Regards