Ques 9

Q9. A particle is moving along a straight line such that its velocity varies with position as shown in figure, then the acceleration of the particle at x = 10 m is 
                 
                       
        (1) – 4.6 m/s2                                            (2) –6.8 m/s2


        (3) –8.9 m/s2                                            (4) – 10.6 m/s2
 

a=v.dvdx  follow the this formula .dvdx= is the slope of the line dvdx=-2015=-43  s-1velocity at x=10 m 2015=v15-10v=203 m/sa=203*-43=-8.9 m/s2Regards

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