Ques 9 Q9. A particle is moving along a straight line such that its velocity varies with position as shown in figure, then the acceleration of the particle at x = 10 m is (1) – 4.6 m/s2 (2) –6.8 m/s2 (3) –8.9 m/s2 (4) – 10.6 m/s2 Share with your friends Share 33 Shobhit Mittal answered this a=v.dvdx follow the this formula .dvdx= is the slope of the line dvdx=-2015=-43 s-1velocity at x=10 m 2015=v15-10v=203 m/sa=203*-43=-8.9 m/s2Regards 30 View Full Answer