Question
1) Calculate the work done in kilo joules when 2 mole of an ideal gas expand isothermally from 10 dm3 to 60 dm3 against constant pressure of one atmosphere at 298 K
Solution w = -p(v2-v1)
= -1.013× 10-5× 5 ×10-3
How to solve proceed solution
Work done for isothermal expansion at constant pressure is given by
w = -pdV
where p is pressure and dV is change in volume
dV = V2- V1
where V1 and V2 are initial and final volume respectively.
dV = 60 -10
= 50 dm3
= 50 10-3 m3
w = -pdV
p = pressure
p = 1 atm or 1.01325 X 105 Pa
w = -1.01325 10550 10-3
= 50.6625 102 J
w = -pdV
where p is pressure and dV is change in volume
dV = V2- V1
where V1 and V2 are initial and final volume respectively.
dV = 60 -10
= 50 dm3
= 50 10-3 m3
w = -pdV
p = pressure
p = 1 atm or 1.01325 X 105 Pa
w = -1.01325 10550 10-3
= 50.6625 102 J