Question

1) Calculate the work done in kilo joules when 2 mole of an ideal gas expand isothermally from 10 dm3 to 60 dm3 against constant pressure of one atmosphere at 298 K

Solution w = -p(v2-v1)

= -1.013× 10-⁵× 5 ×10^-3

How to solve proceed solution

Work done for isothermal expansion at constant pressure is given by 
w = -pdV
where p is pressure and dV is change in volume
dV = V₂- V₁
where V₁  and V₂ are initial and final volume respectively.
dV = 60 -10
= 50 dm³
= 50 $\times$ 10^-3 m³
w = -pdV
​p = pressure 
p = 1 atm or 1.01325 $\times$X 10⁵ Pa
w = -1.01325 $\times$10⁵$\times$50  10^-3
= 50.6625 $\times$ 10² J
​