Question 12 please..
Dear student,
Let the angles be a-d, a, a+d
Let the angles be a-d, a, a+d
Sum of angles of a triangle= 180°
a-d+a+a+d=180°
3a=180°
a=60°
Here, let assume greatest angle is a+d and least is a-d
a-d+a+a+d=180°
3a=180°
a=60°
Here, let assume greatest angle is a+d and least is a-d
Given,
a+d=2(a-d)
a+d=2a-2d
a=3d
so, d=20°
Therefore angles are:
a+d=60°+20°=80°
a=60°
a-d=40°
Regards
a+d=2(a-d)
a+d=2a-2d
a=3d
so, d=20°
Therefore angles are:
a+d=60°+20°=80°
a=60°
a-d=40°
Regards