Question 20 first part. Pls dont send any links Q.20 E is any point on the side DC of the parallelogram ABCD. Extened AE cuts extended BC at point F. Prove that a r ( ∆ A D F ) = a r ( ∆ A B E ) Share with your friends Share 0 Lovina Kansal answered this Dear student As △ADF and △ABD are on the same base AD and between same parallels AD and BC.∴ar(△ADF)=ar(△ADB) ...(1)Similarly, △ADB and △ABE are on the same base AB and between same parallels AB and DC.∴ar(△ADB)=ar(△ABE) ...(2)From (1) and (2),we getar(△ADF)=ar(△ABE) Hence proved Regards 0 View Full Answer