Question 3 pls Share with your friends Share 0 Sejal Gupta answered this Solution : 3. For train A:Speed of train A=72 km/h=72×10003600=20 m/sAcceleration, a=0Time, t=50 secDistance covered, s=ut+12at2=20×50+0=1000 mFor train B:Speed=72 km/h=20 m/sAcceleration, a=1 m/s2Time, t=50 secDistance covered by B, s=20×50+12×1×502=2250 mThe original distance between A and B=2250-1000=1250 m 0 View Full Answer