Dear Student, For complete neutralisation, N1V1 (NaOH) = N2V2(Oxalic acid)or, N1×20=0 1×20or, N1=0 1and Normality, N =MassEquivalent mass×1000Volume of solutionor, 0 1=Mass40×1000250or, Mass of NaOH= 0 1×40×2501000=1 gTherefore, the nearest option is (B)

question 45

Dear Student,

For complete neutralisation, N_{1} V_{1} (NaOH) = N_{2} V_{2} (Oxalic acid) or, N_{1} \times 20 = 0.1 \times 20 or, N_{1} = 0.1 and Normality, N = \frac{Mass}{Equivalent mass} \times \frac{1000}{Volume of solution} or, 0.1 = \frac{Mass}{40} \times \frac{1000}{250} or, Mass of NaOH = \frac{0.1 \times 40 \times 250}{1000} = 1 g Therefore, the nearest option is (B)

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