Question 5 i & ii Share with your friends Share 0 Rahul K answered this 1 View Full Answer S Ramaratnam answered this in a triangle A+B+C = 180 (A+B+C)/2 = 90 thus (A+B)/2 = 90 - C/2 (B+C)/2 = 90 - A/2 thus sin((A+B)/2 ) = sin ( 90 -C/2) = cos(C/2) tan( (B+C)/2 ) = tan ( 90 - A/2 ) = cot(A/2) 0