Question) Calculate the RMS value of alternating current shown in the figure.

I rms = root i1^2+i2^2+i3^2/3 which leads to 2A
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i think it would be 2/root 2 that is root 2
 
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I rms = root i1^2+i2^2+i3^2/3 which leads to 2A
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Ans =2A

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2Adhdu
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In this question 2/root2 (2 being the peak current)  is invalid because 1/root2 is definite integral of sin wave a.c. in this case the graph is not of sin wave but rather a square wave a.c. which have RMS value = PEAK value.
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What are you looking for?