QUESTION FROM SANIYAH , OUR OWN ENGLISH HIGH SCHOOL RIDHIMA IS 5 YRS YOUNGER THAN AARAV. FOUR YRS LATER , AARAV WILL BE TWICE AS OLD AS RIDHIMA . FIND THEIR PRESENT AGE. IN THE ABOVE QUESTION , THERE IS A STEP IN WHICH IT IS WRITTEN x + 5 . I DID NOT UNDERSTAND HOW X + 5 IS WRITTEN WHEN IT WAS WRITTEN IN THE QUESTION 4 YRS LATER. PLEASE CLEAR M DOUBT , MERITNATION EXPERTS. Share with your friends Share 1 Manbar Singh answered this Let the present age of Aarav = x yrsNow, present age of Ridhima = x-5 yrs4 YEARS LATER :Aarav's age = x + 4 yrsRidhma's age = x-5 + 4 = x-5+4 = x - 1 yrsNow, according to question : x + 4 = 2x - 1⇒x + 4 = 2x - 2⇒x - 2x = -2 - 4⇒-x = -6⇒x = 6So, present age of Aarav = 6 yrsPresent age of Ridhima = 6 - 5 = 1 yr 3 View Full Answer