QUESTION FROM SANIYAH , OUR OWN ENGLISH HIGH SCHOOL
RIDHIMA IS 5 YRS YOUNGER THAN AARAV. FOUR YRS LATER , AARAV WILL BE TWICE AS OLD AS RIDHIMA . FIND THEIR PRESENT AGE. 
IN THE ABOVE QUESTION , THERE IS A STEP IN WHICH IT IS WRITTEN x + 5 . I DID NOT UNDERSTAND HOW X + 5 IS WRITTEN  WHEN IT WAS WRITTEN IN THE QUESTION 4 YRS LATER.

PLEASE CLEAR M DOUBT , MERITNATION EXPERTS.


 

Let the present age of Aarav = x yrsNow, present age of Ridhima = x-5 yrs4 YEARS LATER :Aarav's age = x + 4 yrsRidhma's age = x-5 + 4 = x-5+4 = x - 1 yrsNow, according to question :   x + 4 = 2x - 1x + 4 = 2x - 2x - 2x = -2 - 4-x = -6x = 6So, present age of Aarav = 6 yrsPresent age of Ridhima = 6 - 5 = 1 yr

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