Question) In the adjoining figure, OACB is a quadrant of a circle of a radius 7 cm. The perimeter of quadrant is .
$$\begin{gathered} a) 11 cm \\ b) 18 cm \\ c) 25 cm \\ d) 36 cm \end{gathered}$$

Here,
radius=7 cm,
thetha=90degee    (Quadrant of circle)
we know that,
peimeter of quadrant(sector) = thetha/360*2(pie)(radius)
                                               = 90/360 * 2*22/7*7
                                               = 1/4 * 2*22
                                               = 11
peimeter of quadrant(sector) = 11 cm
option (a) is correct