question no. 11

Dear Student,

Please find below the solution to the asked query:

Given that the angular velocity of the table is,

ωtab=π6 rads.

Now, the angular velocity of the person B with respect to the table is,

ω2=v2r-ωtab=v23-π6So,If ω1=5π6 rads and ω2=π3-π6ω2=π6Therefore, the time taken by B to catch A is,t=θω1-ω2=π65π6-π6=14 sIf ω1=4π6 rads and ω2=π3-π6ω2=π6Therefore, the time taken by B to catch A is,t=θω1-ω2=π64π6-π6=13 sIf ω1=4π3 rads and ω2=2π3-π6ω2=π3Therefore, the time taken by B to catch A is,t=θω1-ω2=π64π3-π3=12=0.5 sIf ω1=π6 rads and ω2=2π3-π6ω2=π3Therefore, the anglar velociy of B is more than the angular velocity of A.

So, A will not reach B within a time 0.2 s.


Hope this information will clear your doubts about the topic.

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