Question No.29

Dear Students,


f(x)= x+$\sqrt{x^2}$
We can write f(x) in another way;
 
f(x)= x+x   if x>=0
        x-x    if x<0

So, f(x) = 2x if x>=0
            = 0   if x<0

Here f(x) is mapped to R$\to$R

But we see from f(x) that, when x<0 f(x)=0, means every 'x' of function is mapped to 0

So this function is niether one-one nor onto.  

Regards.