Question no 3 3. A point E is taken on the side CD of a parallelogram. ABCD and CD is produced to F so that DF = CE. BE produced meets AD produced in G and the line through F parallel to AG is FH and H lies on produced part of BE. Prove that area of parallelogram AFHG = area of parallelogram ABCD. Share with your friends Share 5 Surabhi Grover answered this Dear Student, Consider the following figure: Area of || gm ABEF= Area of || gm ABCD (Having common base AB and between the same parallels)Area of || gm ABEF= Area of || gm AFGH(Having common base AF and between the same parallels)Hence Area of || gm ABCD =Area of ||gm AFGH Hence Proved 9 View Full Answer Mohammed Faraz answered this can't see -9 Anushka Maurya answered this :( -8