Question no 3

3.  A point E is taken on the side CD of a parallelogram. ABCD and CD is produced to F so that DF = CE. BE produced meets AD produced in G and the line through F parallel to AG is FH and H lies on produced part of BE. Prove that area of parallelogram AFHG = area of parallelogram ABCD. 
 

Dear Student, 
Consider the following figure:

Area of || gm ABEF= Area of || gm ABCD (Having common base AB and between the same parallels)Area of || gm ABEF= Area of || gm AFGH(Having common base AFand between the same parallels)Hence   Area of || gm ABCD =Area of ||gm AFGH
Hence Proved
 

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