question no. 4 question no. 4 5. If x then x Share with your friends Share 0 Bhavika Jangid answered this Ans to it is 1 View Full Answer Jayesh Dharmale answered this Let a=√2+1 & b=√2-1 Then , x³+3x=a³•⅓+b³•⅓-3a⅓•²b⅓ +3a⅓b²•⅓+3(a-b)⅓ =a-b-3(ab)[a-b]⅓+3(a-b)⅓ Substitute, a=√2+1 b=√2-+1 √2+1-(√2-1) -3[(√2+1)(√2-1)]⅓[√2+1-√2-1] + 3[√2+1-√2-1]⅓ =2 - 3×1×2⅓+3×2⅓ =2-6⅓+6⅓ =2 1
