Question no. 6. A machine gun fires a bullet of mass 50 gm with velocity 1000 m/s. If average force acting on gun is 200 N then find out the maximum number of bullets fired per minute.

Dear student,
impulse=change in momentumF×t=m(v-u)nn= number of bullets in 60sec200×60=0.050×1000×nn=120000.050×1000=240Regards

 

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