question no. 8

question no. 8 In AABC, if AD is a median, then prove B. 9. Prove that secA + tanA—1 secA + tanA+1 1 +sinA cosA If 2cos0 — Sino = x and cos0-3sin9= 2x2 + - 2xy = 5 Draw less than type ogive for the foll Median. Scores

nope.. its not the textbook one

May be your question is wrong

According to me the right question with solution

Answers


L.H.S = 1 + secA ? tanA / 1 + secA + tanA? ? ? ? ? ?,? R.H.S =1 ? sinA / cosA????

= L.H.S(sec2A ? tan2A) + secA ? tanA / 1 + secA + tanA

As we know that [sec2A ? tan2A = 1]

So here L. H. S= (secA ? tanA) (secA + tanA) + (secA ? tanA) / 1 + secA + tanA

We know about this formula [a2+b2=(a+b) (a-b)]

L.H.S = (secA ? tanA) (1+secA + tanA) / 1 + secA + tanA

L.H.S = secA ? tanA

We know about the formula of secA and tanA,[secA = 1 / cosA], [ tanA = sinA / cosA]

?putting the value of secA and tanA

so = 1 / cosA - sinA / cosA

L.H. S= 1 ? sinA / cosA

So here L.H. S is equal to R.H.S

Are you satisfy with me or not ???

can you write and give because im unable to understand because in many placess ? sign is coming

Pls tell me from where u can't understund

plus minus and some other signs are coming As question mark so if you dont mind can you send me by writing in a sheet...

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