Question number 27

Dear Student,
Please find below the solution to the asked query:

x2a2+y2b2=1x2a2=1-y2b2x2=a21-y2b2Let point be x1,y1 so it will lie on ix12=a21-y12b2Differentiate i with respect to x2xa2+2yb2.dydx=0dydx=-2xa2.b22y=-b2a2xydydxx1,y1=-b2a2x1y1We know that length of normal is given byL=y1+dydx2L=y11+b4a41y12.a21-y12b2=y11+b4a21y121-y12b2=y11+b4a2y12-b2a2

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