Question) PQRS is a parallelogram. ST and QX are perpendicular to PR. ST = QX. Prove that the triangle SPT congruence triangle QRX.

Given PQRS is a parallelogram SPT is SPC is lying on diagonal PR and triangle to Alex lies on diagonal we are also St is equal to Q was given now in triangle abc and triangle Kyun RX angle TPS is equal to angle execute their alternate angles is equal to q x it is given angle PTS is equal to angle r x cube equal to 90 degree given that 4 triangle SPT is coming to triangle pqr x
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Given PQRS is a parallelogram. Shown SQ and PR are diagonals and triangle PST and triangle QRX are lying on diagonal PR Now triangle PST and triangle QRX, ST=QX (given) angle PTS=angle QXR=90 degree (given) PS = QR (given parallel sides of parallelogram ) therefore triangle PST and triangle QRX are congruent (by SAS)
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Phanindra
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