Question :
The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9:7.
Find the their present ages(solution with statement).
Let the present age of Leena = 7xyears
And present age of Heena = 5x years
After ten years their ages will be
Leena = (7x + 10)yrs and
Heena = (5x + 10)yrs
Now the ratio of their ages after 10 years is 9: 7.
Therefore, we get
(7x + 10)/ 5x + 10) = 9/7
49x + 70 = 45x + 90
49x – 45x = 90 – 70
4x = 20
x= 5.
Therefore,
Present age of Leena = 7×5 = 35 years.
And present age of Heena = 5×5 = 25 years.