Question :

The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9:7.

Find the their present ages(solution with statement).

Let the present age of Leena = 7xyears

And present age of  Heena = 5x years

After ten years their ages will be

Leena =  (7x + 10)yrs and

Heena = (5x + 10)yrs

Now the ratio of their ages after 10 years is 9: 7.

Therefore, we get

(7x + 10)/ 5x + 10) = 9/7

49x + 70 = 45x + 90

49x – 45x = 90 – 70

4x = 20

x= 5.

Therefore,

Present age of Leena = 7×5 = 35 years.

And present age of Heena = 5×5 = 25 years.

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