Dear Student, vrms=3RTMwhere, M is the molar massM = Mass of molecule×NATherefore, vrms=3×(8 314 JK-1mol-1)×(300 K)10-12×6 022×1023×10-3 kgmol=1242 5×10-8= 35 24×10-4 m/s = 0 35 cm/sHence, correct answer is (B)

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Dear Student,

v_{rms} = \sqrt{\frac{3 RT}{M}} where, M is the molar mass M = Mass of molecule \times N_{A} Therefore, v_{rms} = \sqrt{\frac{3 \times (8.314 {JK}^{- 1} {mol}^{- 1}) \times (300 K)}{10^{- 12} \times 6.022 \times 10^{23} \times 10^{- 3} kgmol}} = \sqrt{1242.5 \times 10^{- 8}} = 35.24 \times 10^{- 4} m / s = 0.35 cm / s Hence, correct answer is (B)

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