Question- Share with your friends Share 0 Sanjay Singh answered this Dear student Equivalent capacitance in the first case is 1Ceqv=12C+12C1Ceqv=22C=1CCeqv=CEnergy stored is U1=12CE2...1In the second case potential difference across the left capacitor is =E as it is directly connected withthe cell.So energy stored in it is U3=12×(2C)×E2=CE2and the capacitor on the right is shrt circuited and so charge on becomes zero and it does not store any energy.so total energy stored isU2=CE2U1U2=12CE2CE2=12Regards 1 View Full Answer Abdul Mannan Akhtar answered this Answer is 1/4 in first case capacitor are series after key is closed the parallels 0
