Dear student T=2πlg∆TT=12×∆gg and ∆gg =-2hR∆TT=12×-2hR=-hRso time lost in 1 day ∆TTday=-hR×86400 second=-2006 4×106×86400 second =2 7 second lostRegards

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T = 2 π \sqrt{\frac{l}{g}} \frac{∆ T}{T} = \frac{1}{2} \times \frac{∆ g}{g} a n d \frac{∆ g}{g} = \frac{- 2 h}{R} \frac{∆ T}{T} = \frac{1}{2} \times \frac{- 2 h}{R} = \frac{- h}{R} s o t i m e l o s t i n 1 d a y {(\frac{∆ T}{T})}_{d a y} = \frac{- h}{R} \times 86400 s e c o n d = \frac{- 200}{6.4 \times 10^{6}} \times 86400 s e c o n d = 2.7 s e c o n d l o s t R e g a r d s

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