Questions 1and 2 without breaking mid terms Share with your friends Share 0 Sneha Apar answered this 0 View Full Answer Navin Saxena answered this i). x^2-6x+3=0, OR (x - 3)^2-6=0, OR (x - 3)^2=(√6)^2, x - 3 =+/- √6, x= 3 +/- √6 ii). x^2-4x+1=0, OR (x-2)^2 -3=0, (x-2)= +/-√3, x=2 +/- √3 0