Raghav applies a force of 6kgf to draw 4.8kg bucket of water from a well using a single fixed pulley. Assuming that all of the extra force a applied is to overcome frictional forces, calculate the force of friction, mechanical advantage and efficiency.

Given thatE=6kgf=6×10 N=60NL=4.8kgf=4.8×10N=48NE=T=L+friction forceSo,friction force,f=E-L=60-48=12NMechanical advantage=L/E=48/60=0.80NNow,efficiency η=Mechanical advantage(MA)/Velocity ratio(VR)For a single fixed pulley,VR=1So,η=MA/1=0.80/1=0.80Or 80%

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