Ramu's father is four times as old as Ramu. After 16 years,he will be just twice his son. find their present age.
Let the present age of Ramu be x years.
thus the age of ramu's father=4x yrs.
ramu's age after 16 yrs.=x+16
ramu's father's age after 16 years=4x+16 yrs.
2x=16 => x=8
thus the present age of Ramu=8 yrs. and the age of ramu's father=32 yrs.
let ramu's present age be 'x' and his father's age be 'y'
after 16 year's
substitute 1 in 2
plug x value into 1 to get y value
therefore ramu's age=8 years and
father's age=32 years
Ramu's age = x yrs
Ramu's father age = 4x yrs
Ramu's age after 16 yrs = (x + 16) yrs = x + 16 years
Ramu's father age after 16 yrs = (4x + 16) yrs = 4x + 16 yrs
= 4x + 16 = 2(x + 16)
= 4x + 16 = 2x + 32
= 4x - 2x = 32 - 16
= 2x = 16
= x = 16/2 = 8
Therefore, Ramu's present age is 8 yrs and his father's age is 32 yrs.