# Ramu's father is four times as old as Ramu. After 16 years,he will be just twice his son. find their present age.

Let the present age of Ramu be x years.

thus the age of ramu's father=4x yrs.

ramu's age after 16 yrs.=x+16

ramu's father's age after 16 years=4x+16 yrs.

4x+16=2(x+16)

2x=16 => x=8

thus the present age of Ramu=8 yrs. and the age of ramu's father=32 yrs.

• 4

let ramu's present age be 'x' and his father's age be 'y'

y=4x-----1

after 16 year's

ramu's age=x+16

father's age=y+16

2(x+16)=y+16

2x+32=y+16

y-2x=16-------2

substitute 1 in 2

4x-2x=16

2x=16

x=8

plug x value into 1 to get y value

y=4*8

y=32

therefore ramu's age=8 years and

father's age=32 years

• 0

well done

• 2

Ramu's age = x yrs

Ramu's father age = 4x yrs

Ramu's age after 16 yrs = (x + 16) yrs = x + 16 years

Ramu's father age after 16 yrs = (4x + 16) yrs = 4x + 16 yrs

= 4x + 16 = 2(x + 16)

= 4x + 16 = 2x + 32

= 4x - 2x = 32 - 16

= 2x = 16

= x = 16/2 = 8

Therefore, Ramu's present age is 8 yrs and his father's age is 32 yrs.

• -1

et ramu's present age be 'x' and his father's age be 'y'

y=4x-----1

after 16 year's

ramu's age=x+16

father's age=y+16

2(x+16)=y+16

2x+32=y+16

y-2x=16-------2

substitute 1 in 2

4x-2x=16

2x=16

x=8

plug x value into 1 to get y value

y=4*8

y=32

therefore ramu's age=8 years and

father's age=32 years

• 0
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