range of (4^x)+(2^x)+1 is

Hi  Kshitij,
Please find below the solution to the asked query:

fx=4x+2x+1f'x=4x.ln4+2x.ln2Now since ax is always positive,f'x>0 for all xRfx is an increasing function. Hence it will have its minimum value when x- and maximum value when xNow limx -ax=0limx -4x+2x=0Hence min value of fx=4x+2x+1 will tend towards 1 and it is clear that maximum value will tend towards .Hence range of fx=4x+2x+1 is 1,  

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

  • 0
What are you looking for?