ratio of frequencies of revolution of electrons in the second excited state of He+ to the second state of hydrogen is 
a. 32/27
b.27/32
c.1/54
d.27/2

Dear student,
Please find the solution to the asked query:

f1/f2 = z13/n12 x n22/z23   [Ratio of frequencies of electron in the second state of He+ to the second state of Hydrogen]
   Substituting the values n1= 3, z1 = 2, z2=1 , n2 = 2 we get
     f1/f2 =  32/27

Hence option A is the correct answer.
Regards

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