Ravish sold his cycle to Vineet at a loss of 28% Vineet spent Rs 1680 on it's repairs and - Maths - Comparing Quantities

Question

Ravish sold his cycle to Vineet at a loss of 28% Vineet spent
Rs 1680 on it's repairs and sold it to Rahul for Rs 35910, thereby
making a profit of 12 5%, find the original cost price
A toy was sold at a gain of 12% Had it been sold for Rs 33
more, the gain would have been 14% Find the cost price of the
toy
A man bought an article and sold it at a gain of 10%, If he had
bought it for 20% less and sold it for Rs 10 more, he would have
made a profit of 40% Find the cost price of the article

Lalit Mehra · Accepted Answer

Dear Student! 1 Let the original cost price of the cycle be Rs x Selling price of cycle to Ravish = Rs x â€“ 28% of Rs x $= Rs x - \frac{28}{100} \times Rs x = Rs \frac{72}{100} x$ âˆ´ Cost price of cycle to Vineet = $Rs \frac{72}{100} x$ Amount spent by Vineet on the cycle = Rs 1680 âˆ´ Net cost price of cycle to Vineet $= Rs (\frac{72}{100} x + 1680)$ Selling price of cycle to Vineet = Rs 35910 Profit to Vineet = $Rs 35910 - Rs (\frac{72}{100} x + 1680)$ $= Rs (34230 - \frac{72}{100} x)$ We know that, $Profit% = \frac{Profit}{C P} \times 100 % \Rightarrow 12 5 = \frac{Rs (34230 - \frac{72}{100} x)}{Rs (\frac{72}{100} x + 1680)} \times 100 \Rightarrow 12 5 \times \frac{72}{100} x + 21000 = 3423000 - 100 \times \frac{72}{100} x \Rightarrow \frac{72}{100} x (12 5 + 100) = 3423000 - 21000 \Rightarrow \frac{72}{100} x \times 112 5 = 3402000 \Rightarrow x = \frac{3402000 \times 100}{72 \times 112 5} = 42000$ Thus, the original cost of cycle is Rs 42000 2 Let the cost price of the toy be Rs x Gain% = 12% Selling price of the toy = Rs x + 12% of Rs x = $Rs x + \frac{12}{100} \times Rs x = Rs \frac{112}{100} x$ If the toy was sold for Rs 33 more, then New selling price of the toy = Rs $\frac{12}{100} x + Rs 33 = Rs (\frac{112}{100} + 33)$ Gain = $Rs (\frac{112}{100} x + 33) - Rs x = Rs (\frac{12}{100} x + 33)$ $Gain% = \frac{Gain}{C P} \times 100 % \Rightarrow 14 = \frac{Rs (\frac{12}{100} x + 33)}{Rs x} \times 100 \Rightarrow \frac{14}{100} x = \frac{12}{100} x + 33 \Rightarrow \frac{14}{100} x - \frac{12}{100} x = 33 \Rightarrow \frac{2 x}{100} = 33 \Rightarrow x = \frac{3300}{2} = 1650$ Thus, the cost price of the toy is Rs 1650 We are happy to see the interest you are showing towards this section! Thank you for your response I have solved two of your queries However, due to a paucity of time we will not be able to immediately answer all your queries Try to solve the remaining question If you have any problem in solving it, then get back to us we will be happy to help you Cheers!