Reaction between N2 and O2 takes place as follows: If a mixture of 0 482 mol of N2 and - Chemistry - Equilibrium

Question

Reaction between N2 and O2 takes place as
follows:

If a mixture of 0 482 mol of N2 and 0 933 mol of
O2 is placed in a 10 L reaction vessel and allowed to
form N2O at a temperature for which K
c = 2 0 × 10–37, determine
the composition of equilibrium mixture

Prerna Bansal · Accepted Answer

Let the concentration of N2O at equilibrium be x The given reaction is:

Therefore, at equilibrium, in the 10 L vessel:

The value of equilibrium constant i e ,

= 2 0 × 10–37 is very small Therefore, the amount of N2 and O2 reacted is also very small Thus, x can be neglected from the expressions of molar concentrations of N2 and O2 Then,

Now,

Reaction between N2 and O2 takes place as follows: If a mixture of 0.482 mol of N2 and 0.933 mol of O2 is placed in a 10 L reaction vessel and allowed to form N2O at a temperature for which K c = 2.0 × 10–37, determine the composition of equilibrium mixture.

Reaction between N₂ and O₂ takes place as follows:

If a mixture of 0.482 mol of N₂ and 0.933 mol of O₂ is placed in a 10 L reaction vessel and allowed to form N₂O at a temperature for which K _c = 2.0 × 10^–37, determine the composition of equilibrium mixture.