reduce the equation x+y-root 2 =0 to the normal form x cos alpha +y sin alpha = p and hence find values of alpha and p

The given equation is,    x + y - 2 = 0x + y = 2x12 + 12 + y12 + 12 = 212 + 12x2 + y2 = 1So, we get cos α = 12 and sin α = 12  and p =1Since, cos α > 0  and sin α >0, so α lies in first quadrant.Now, sin αcos α = 1/21/2 tan α = 1α = 45°So, given equation in normal form is,x cos 45° + y sin 45° = 1

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